Webwhere R S is the Schwarzschild radius, G is the gravitational constant, M is the mass of the object and c is the speed of light. The following table gives the Schwarzschild radii of some familiar astronomical objects: Object Mass R S: Sun: 2.0 × 10 30 kg : 3.0 × 10 3 m = 3 km : Earth : 6.0 × 10 24 kg : 8.7 × 10-3 m = 8.7 mm : Moon: WebAug 25, 2024 · Step 6 - Calculating the Earth and the Sun Schwarzschild radius. Assuming that they are both spherically symmetric bodies, we can calculate the Schwarzschild radius of the Earth and the Sun. Starting …
Gravitational Acceleration in Schwarzschild Coordinates
WebA particle is moving in a Schwarzschild spacetime around a star of mass M. It moves in a circle at a Schwarzschild coordinate radius r at an angular frequency as seen at inflnity of ›. That is, d`=dt = ›, where t is the Schwarzschild coordinate time. What is the speciflc angular momentum at inflnity u` of the particle? This is a useful ... WebMar 19, 2024 · The Schwarzschild radius is assumed to be: rs = 2m, where the m has been assumed to be an atomic standard mass, ie. it's the fantastic newtonian - invariant, indestructible mass. So, where is a formal derivation of this quantity in the GR domain? Tom Roberts. unread, hilliard ohio dog shelter adoptable dogs
where is the derivation of the Schwarzschild radius? - Google …
WebNov 17, 2024 · The Schwarzschild radius is of the order of milimiters for the Earth (8.881e-3 meters) and the order of kilometers for the Sun (2,97024415e3 meters)! Problem Recent Solvers 47 . Suggested Problems. Find the numeric mean of the prime numbers in a matrix. 8090 Solvers. Trimming Spaces. Webreview derivation: Schwarzschild radius for non-rotating black hole. This page contains three views of the steps in the derivation: d3js, graphviz PNG, and a table. Hold the … WebNov 16, 2010 · the derivation of the schwarzschild radius comes from the fact that at the event horizon the gravitational potential energy is equal to the kinetic energy it had went in left the singularity... i know this is a classical method and quite simple but it works and that is 1/2 mV^ (2) = GMmr^ (-1) r = 2GMV^ (-2) in this case V = C so; r = 2GMV^ (-2) smart electric hvac